Odpowiedź:
a) [tex]\sqrt{108} = \sqrt{36*3} = 6\sqrt{3}[/tex]
b ) [tex]\sqrt[3]{-392} = - \sqrt[3]{2^3*49} = -2 \sqrt[3]{49}[/tex]
c ) [tex]\sqrt[5]{3^{12}} = \sqrt[5]{(3^2)^5 *9} = 9 \sqrt[5]{9}[/tex]
d ) [tex]\sqrt[6]{2^{11}} = \sqrt[6]{2^6*2^5} = 2\sqrt[6]{2^5} = 2 \sqrt[6]{32}[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
a) [tex]\sqrt{108} = \sqrt{36*3} = 6\sqrt{3}[/tex]
b ) [tex]\sqrt[3]{-392} = - \sqrt[3]{2^3*49} = -2 \sqrt[3]{49}[/tex]
c ) [tex]\sqrt[5]{3^{12}} = \sqrt[5]{(3^2)^5 *9} = 9 \sqrt[5]{9}[/tex]
d ) [tex]\sqrt[6]{2^{11}} = \sqrt[6]{2^6*2^5} = 2\sqrt[6]{2^5} = 2 \sqrt[6]{32}[/tex]
Szczegółowe wyjaśnienie: