a) [tex]\frac{29}{6} = \frac{4 \times 6 + 5}{6} = 4\frac{5}{6}[/tex]
b) [tex]\frac{15}{7} = \frac{2 \times 7 + 1}{7} = 2\frac{1}{7}\\\frac{28}{9} = \frac{3 \times 9 + 1}{9} = 3\frac{1}{9}[/tex]
c) [tex]\frac{84}{10} = \frac{8 \times 10 + 4}{10} = 8\frac{4}{10} = 8\frac{2}{5}\\\frac{78}{25} = \frac{3 \times 25 + 3}{25} = 3\frac{3}{25}[/tex]
d)[tex]\frac{203}{2} = \frac{101 \times 2 + 1}{2} = 101\frac{1}{2}\\\frac{104}{3} = \frac{34 \times 3 + 2}{3} = 34\frac{2}{3}[/tex]
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Verified answer
a) [tex]\frac{29}{6} = \frac{4 \times 6 + 5}{6} = 4\frac{5}{6}[/tex]
b) [tex]\frac{15}{7} = \frac{2 \times 7 + 1}{7} = 2\frac{1}{7}\\\frac{28}{9} = \frac{3 \times 9 + 1}{9} = 3\frac{1}{9}[/tex]
c) [tex]\frac{84}{10} = \frac{8 \times 10 + 4}{10} = 8\frac{4}{10} = 8\frac{2}{5}\\\frac{78}{25} = \frac{3 \times 25 + 3}{25} = 3\frac{3}{25}[/tex]
d)[tex]\frac{203}{2} = \frac{101 \times 2 + 1}{2} = 101\frac{1}{2}\\\frac{104}{3} = \frac{34 \times 3 + 2}{3} = 34\frac{2}{3}[/tex]