Odpowiedź:
[tex]a_n = - 3 n^2 - 6 n + 74 < 50\\- 3 n^2 - 6 n + 24 < 0 / : 3\\- n^2 - 2 n + 8 < 0[/tex]
Δ = ( - 2)² - 4*(- 1)*8 = 4 + 32 = 36 √Δ = 6
n = [tex]\frac{2 - 6}{- 2} =2[/tex] lub n = [tex]\frac{2 + 6}{- 2} = - 4[/tex]
Odp. n > 2 czyli [tex]a_3, a_4, a_5, ...[/tex]
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Odpowiedź:
[tex]a_n = - 3 n^2 - 6 n + 74 < 50\\- 3 n^2 - 6 n + 24 < 0 / : 3\\- n^2 - 2 n + 8 < 0[/tex]
Δ = ( - 2)² - 4*(- 1)*8 = 4 + 32 = 36 √Δ = 6
n = [tex]\frac{2 - 6}{- 2} =2[/tex] lub n = [tex]\frac{2 + 6}{- 2} = - 4[/tex]
Odp. n > 2 czyli [tex]a_3, a_4, a_5, ...[/tex]
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Szczegółowe wyjaśnienie: