Penjelasan dengan langkah-langkah:
[tex]y = g(x) = \frac{5x - 1}{4 - 3x} \\ y(4 - 3x) = 5x - 1 \\ 4y - 12xy = 5x - 1 \\ - 12xy - 5x = -4y - 1 \\ x( - 12y - 5) = - 4y - 1 \\ x = \frac{ - 4y - 1}{ - 12y - 5} \\ f {}^{ - 1} (x) = \frac{ - 4x - 1}{ - 12x -5 } [/tex]
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Penjelasan dengan langkah-langkah:
[tex]y = g(x) = \frac{5x - 1}{4 - 3x} \\ y(4 - 3x) = 5x - 1 \\ 4y - 12xy = 5x - 1 \\ - 12xy - 5x = -4y - 1 \\ x( - 12y - 5) = - 4y - 1 \\ x = \frac{ - 4y - 1}{ - 12y - 5} \\ f {}^{ - 1} (x) = \frac{ - 4x - 1}{ - 12x -5 } [/tex]