wode zmieszano z NaOH w stosunku masowym 15:1. oblicz Cp roztworu
mNaOH= 23+16+1= 40u = 40g
MH2O= 2*1u+16u= 18u= 18g
mw=15*18=270g
ms= 40g
mr= 270g+40g=310g
Cp= ms*100%/mr
Cp= 40*100/310
Cp= 12,9 = około 13%
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mNaOH= 23+16+1= 40u = 40g
MH2O= 2*1u+16u= 18u= 18g
mw=15*18=270g
ms= 40g
mr= 270g+40g=310g
Cp= ms*100%/mr
Cp= 40*100/310
Cp= 12,9 = około 13%