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4P + 5o2 -> p4o10
177,5g-100g=77,5g Od uległo spaleniu 77,5 g fosforu :)
2) Oblicz masę tlenku sodu otrzymanego z 2,3g sodu i 1,6g tlenu.
2na + 1/2 o2 -> na20
2,3+1,6=3,9