dane: h = 212 m, m = 60 kg, l = 100 m
szukane: k = ?
E1 = Ep = mgh - energia skoczka na wieży
E2 = Eps = kx²/2 = k(h-l)²/2 - energia skoczka po zatrzymaniu
E1 = E2 (zasada zachowania energii)
mgh = k(h - l)²/2
k = 2mgh/(h-l)² = 2 * 60 kg * 9,8 m/s² * 212 m / (212 m - 100 m)² = 19,875 kg/s²
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dane: h = 212 m, m = 60 kg, l = 100 m
szukane: k = ?
E1 = Ep = mgh - energia skoczka na wieży
E2 = Eps = kx²/2 = k(h-l)²/2 - energia skoczka po zatrzymaniu
E1 = E2 (zasada zachowania energii)
mgh = k(h - l)²/2
k = 2mgh/(h-l)² = 2 * 60 kg * 9,8 m/s² * 212 m / (212 m - 100 m)² = 19,875 kg/s²