Materi : Bentuk Akar dan Pangkat
√(3³) = 3³/² = 3√3
( 5√3 )/( 5√3 ) = (5/5)(√3/√3) = 1.1 = 1
2√18/√3
= ( 2√18 . √3 )/(√3)²
= 2√54/3
= ⅔√(9.6)
= ⅔.3√6
= 2√6
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Bentuk Akar dan Pangkat
√(3³) = 3³/² = 3√3
( 5√3 )/( 5√3 ) = (5/5)(√3/√3) = 1.1 = 1
2√18/√3
= ( 2√18 . √3 )/(√3)²
= 2√54/3
= ⅔√(9.6)
= ⅔.3√6
= 2√6
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]