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T₁=400K V₂=? pV=nRT z tego wynika V₁/T₁=V₂/T₂
T₂=150K
V₁=4m³
Obliczenia:
V₁/T₁=V₂/T₂
V₂=(V₁*T₂)/T₁
V₂=4*150/400=3/2m³
Odp. Po ochłodzeniu gaz zajmuje 3/2m³.