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mCu(OH)₂ = 64u + 32u+ 2u = 98u
mCuSO₄ = 64u + 32u+ 64u = 160u
98u Cu(OH)₂ --- 160u CuSO₄
19,6g Cu(OH)₂ --- x
98x = 160*19,6 /:98
x = 32g
Odp: W tej reakcji zużyto 32g CuSO₄