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201/217 x 100% = 92,62 %
Hg (rtęć) stanowi około 92,62% masy tlenku rtęci
217 g - 16 g = 201 g
201 g / 217 * 100 % ≈ 92, 63 %
Odp. : Rtęć stanowi 92, 63 % masy tlenku rtęci ( II ).
Pozdrawiam! :)
201 g/217 * 100 % = 92, 63 %