W naczyniu zmieszano 70dm3 azotu i 30dm3 wodoru (warunki normalne). Ile moli amoniaku otrzymano?
1dm3 3dm3 2mole
N2 + 3H2 = 2NH3
70dm3 30dm3 xmola=20 moli
70/30=1/3
niedomiar=wodor
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1dm3 3dm3 2mole
N2 + 3H2 = 2NH3
70dm3 30dm3 xmola=20 moli
70/30=1/3
niedomiar=wodor