W jakim czasie silnik dźwigu o mocy 250W podniesie pakę o masie 153 kg na wysokość 10m?
P=W/t -moc
t=W/P
W=mgh
W=153kg·10m/s²·10m=15300J
t=15300J:250W
t=61,2s
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P=W/t -moc
t=W/P
W=mgh
W=153kg·10m/s²·10m=15300J
t=15300J:250W
t=61,2s