1mol H₂S------2*6,02*10²³ at. wodoru
0,5mola H₂S--------x at. wodoru
x = 6,02*10²³ at. wodoru
mNH₃=17u
17g NH₃------3*6,02*10²³ at. wodoru
xg NH₃-----------6,02*10²³ at. wodoru
x = 5,67g NH₃
W 5,67g NH₃ znajduje sie tyle samo atomów wodoru co w 0,5mola H₂S.
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1mol H₂S------2*6,02*10²³ at. wodoru
0,5mola H₂S--------x at. wodoru
x = 6,02*10²³ at. wodoru
mNH₃=17u
17g NH₃------3*6,02*10²³ at. wodoru
xg NH₃-----------6,02*10²³ at. wodoru
x = 5,67g NH₃
W 5,67g NH₃ znajduje sie tyle samo atomów wodoru co w 0,5mola H₂S.