W ile gramach Fe₂O₃ znajduje się 10g Fe?
mFe2O3=2*56g+3*16g=160g
112g----------160g
10g------------xg
xg=10g*160g/112g
xg=14,3g
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mFe2O3=2*56g+3*16g=160g
112g----------160g
10g------------xg
xg=10g*160g/112g
xg=14,3g