W 6dm³roztworu znajduje się 234g roztworu sodu(Na₂S).Oblicz stężenie molowe roztworu.
M Na2S=78 g/mol
n=m/M=234/78=3 mol
Cm=M/V=3/6=0,5mol/dm3
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M Na2S=78 g/mol
n=m/M=234/78=3 mol
Cm=M/V=3/6=0,5mol/dm3