W 250 ml roztworu jest rozpuszczone 26,5g Na2CO3. Oblicz stężenie molowe tego roztworu.
250ml=0,25l=0,25dm3
106g Na2CO3 --- 1 mol
26,5g --- X
X=0,25 mola
Cm=n/V
Cm=0,25/0,25
Cm=1 mol/dm3
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250ml=0,25l=0,25dm3
106g Na2CO3 --- 1 mol
26,5g --- X
X=0,25 mola
Cm=n/V
Cm=0,25/0,25
Cm=1 mol/dm3