Volumen 1 : 1,5 cm3 temperatura 1: 4°C
volumen 2 : 4,5 litros temperatura 2: ?
aplicar ley de charles
volumen 2 : 4,5 litros temperatura 2: ?
aplicar ley de charles
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Volumen1 = 1,5 cm³ = 0,0015 litros
Volumen2 = 4,5 litros
Temperatura 1 = 4°C = -269,15°K
Luego aplicamos ley de Charles:
V1/T1 = V2/T2
Despejando:
T2 = V2*T1/V1