Question

Volume sbh tbng tnpa ttp 785cm³,tinggi'a 10cm,luas tbng tsb adlh..(π=3,14)

Answer 1

V = πr²t
785 = 3,14 × r² × 10
785 = 31,4 × r²
785/31,4 = r²
25 = r²
5 = r

L = 2πr(t+r)
L = 2 × 3,14 × 5 (10 + 5)
L = 31,4 (15)
L = 471 cm²

Answer 2

V. tabung = πr² t
785 = 3,14 r² *10
785= 31,4 r²
785/31,4 = r²
25=r²
√25 =r
5=r

ditanya Luas tabung
Luas tabung tnpa tutup = πr (2t+r)
3,14*5(2*10+5)
15,7(25)
392,5 cm²