PENJELASAN
Volume kerucut :
V = 1/3 x π x r² x t
Mencari tinggi kerucut dengan pytagoras :
t² = s² - r²
t² = 34² - 30²
t² = 1156 - 900
t² = 256
t = √256
t = 16
Volume Kerucut :
V = 1/3 x 3,14 x 30² x 16
V = 1/3 x 3,14 x 900 x 16
V = 1/3 x 3,14 x 14400
V = 1/3 x 45216
V = 15072/3
V = 5024
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PENJELASAN
Volume kerucut :
V = 1/3 x π x r² x t
Mencari tinggi kerucut dengan pytagoras :
t² = s² - r²
t² = 34² - 30²
t² = 1156 - 900
t² = 256
t = √256
t = 16
Volume Kerucut :
V = 1/3 x π x r² x t
V = 1/3 x 3,14 x 30² x 16
V = 1/3 x 3,14 x 900 x 16
V = 1/3 x 3,14 x 14400
V = 1/3 x 45216
V = 15072/3
V = 5024
JADI, volume kerucut tersebut adalah 5024 cm³.