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mencari batas integral
y =0
atau
selanjutnya, tinggal integral tentu seperti biasa
y= X+2
X"-X-2=0
(X-2)(X+1)=0
X=2 V X=-1
V= phi 2 integral -1 {(x+2)^2 - (X^2)^2} dx
= phi 2 integral -1 { (X^2+4x+4-X^4)} dx
= phi [ 1/3X^3 +2X^2 + 4x - 1/5X^5 ] 2 diatas -1 dibawah
= phi ( -1/5 (2)^5 - (-1^5)] + !/3 (2^3 - (-1)^3+ 2[ 2^2- (-1)^2 + 4 (2+1)
= phi (-33/5 +9/3 +6+12)
V= 14 2/5 phi
^= pangkat
kalau belum faham atau penulisan saya kurang bisa dimengerti, boleh bertanya...
terima ksih, semoga bermnfaat