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Persamaan posisi
r(t) = 40t i + (30t - 5t²) j satuan entah apa
untuk t = 0
r(0) = 40·(0) i + (30·(0) - 5·(0)²) j
= 0 i + 0 j
untuk t = 4 s
r(4) = 40·(4) i + (30·(4) - 5·(4)²) j
= 160 i + 40 j
Perpindahan
S = r(4) - r(0)
= 160 i + 40 j - (0 i + 0 j)
= 160 i + 40 j
Besar perpindahan
|S| = √(160² + 40²)
= √(40² 4² + 40²)
= √(40² (4² + 1)
= √(40² · 17)
= 40√17 ≈ 165 m ← jawaban
Arah perpindahan
tan α = 40/160 = ¼
α = 14º ← jawaban
pertanyaan {b} sejenis