Odpowiedź:
Szczegółowe wyjaśnienie:
∪ (-∞; [tex]-\sqrt{2}[/tex]) | ∩ <-4; -2) | a\b (-∞; -4) | b/a <-2; [tex]-\sqrt{2}[/tex])
∪ (-π; ∞) | ∩ <-1/2 ; 1/2> | a/b zbiór pusty | b/a (-π; -1/2)∪(1/2; ∞)
∪ (-∞; ∞) | ∩ [tex]-\sqrt{3}[/tex] | a/b (-∞; [tex]-\sqrt{3}[/tex]) | b/a ([tex]-\sqrt{3}[/tex]; ∞)
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Verified answer
Odpowiedź:
Szczegółowe wyjaśnienie:
∪ (-∞; [tex]-\sqrt{2}[/tex]) | ∩ <-4; -2) | a\b (-∞; -4) | b/a <-2; [tex]-\sqrt{2}[/tex])
∪ (-π; ∞) | ∩ <-1/2 ; 1/2> | a/b zbiór pusty | b/a (-π; -1/2)∪(1/2; ∞)
∪ (-∞; ∞) | ∩ [tex]-\sqrt{3}[/tex] | a/b (-∞; [tex]-\sqrt{3}[/tex]) | b/a ([tex]-\sqrt{3}[/tex]; ∞)