uzupełnij równania reakcji:
Li + S ---> Li(indeks dolny do liczby) 2 S
Pb (indeks dolny do liczby)3 04 + H2 ----> Pb + H2O
Li + S ---> Li(indeks dolny do liczby) 2 S
Pb (indeks dolny do liczby)3 04 + H2 ----> Pb + H2O
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Verified answer
2 Li+S--->Li2S
Pb3O4+4 H2--->3 Pb+4 H2O