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b) 12u*2+4*1u=24u+4u=28u
24u/28u*100%=6/7*100%=600%/7=85,7142857%≈86% (zawartość C)
4u/28u*100%=1/7*100%=100%/7=14,2857143%≈14%(zawartość H)
c) stosunek masowy pierwiastków w etenie
24/4=6/1