Utleniono 2 mole metanolu. Utworzony mmetanal rozpuszczono w 150 ml wody. Odblicz stężenie procentowe metanalu w otrzymanym roztworze.
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2CH3OH + 2CuO---->2HCHO + 2Cu + 2H2O
mHCHO=30u
60g HCHO-------210g roztworu (60g HCHO + 150g wody)
xg HCHO--------100g roztworu
x = 28,57g HCHO
x = 28,57%