ustal wzór sumaryczny i nazwę alkenu, którego masa cząsteczkowa wynosi 70 u
CnH2n = 70 u
C = 12u
H = 1u
12n + 2n = 70u
14n = 70u / (:14)
n = 5
C5H10 PENTEN
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CnH2n = 70 u
C = 12u
H = 1u
12n + 2n = 70u
14n = 70u / (:14)
n = 5
C5H10 PENTEN