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masa węgla 12u
masa wodoru 1u
wzór alkenu CnH2n
12u*n+2u*n=42u
14u*n=42u/:14
n=3
wzór ma postać C₃H₆ czyli propen
CnH2n=42
12n+2n=42
14n=42
n=3
Nasz alken to PROPEN (C₃H₆) CH₂=CH-CH₃