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12n+2n+2=30
14n=28
n=2
C2H6
ETAN
- dla C=1 CH4, M=12 u +4*1 u = 16u
- dla C=2 C2H6, M=2*12 u+ 6*1 u = 30 u
Tym alkanem jest ETAN
C=12u
H=1u
mC2H6=C razy 2+H razy 6=12 razy 2 + 1 razy 6=24+6=30
Odp.ten alkan to etan