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masa O = 16u
masa E = x
x + 2*16 = 239
x + 32 = 239
x = 239-32
x = 207u
pierwiastek E to ołów
wzór tlenku: PbO2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
masa Na2E2O3 = 158u
masa Na = 23u
masa O = 16u
masa E = x
2*23 + 2*x + 3*16 = 158
46 + 2x + 48 = 158
2x = 158-46-48
2x = 64 ||:2
x = 32u
pierwiastek E to siarka
wzór soli: Na2S2O3
239u-(2*16u)=239u-32u=207u
ołów(Pb)
Na2E203 masa 158u
158u-2*23+3*16=158u-46u-48u=64u:2u=32u
siarka(S)