Ustal stosunek masowy pierwiastków w heptanolu, a następnie nazwij ich 3 izomery
mC7H15OH=84u+16u+16u=116u
mC : mH : mO = 84 : 16 : 16
mC : mH : mO = 21 : 4 : 4
CH3-CH2-CH2-CH2-CH2-CH2-CH2-OH ... heptan-1-ol
CH3-CH2-CH2-CH(CH3)-CH2-CH2-OH ... 3-metyloheksan-1-ol
CH3-CH2-CH(CH3)-CH(CH3)-CH2-OH ... 2,3-dimetylopentan-1-ol
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mC7H15OH=84u+16u+16u=116u
mC : mH : mO = 84 : 16 : 16
mC : mH : mO = 21 : 4 : 4
CH3-CH2-CH2-CH2-CH2-CH2-CH2-OH ... heptan-1-ol
CH3-CH2-CH2-CH(CH3)-CH2-CH2-OH ... 3-metyloheksan-1-ol
CH3-CH2-CH(CH3)-CH(CH3)-CH2-OH ... 2,3-dimetylopentan-1-ol