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Verified answer
LISTRIK STATIS• energi
W = 12 J
Q = 2 μC = 2×10⁻⁶ C
∆V = __?
beda potensial
W = Q ∆V
12 = 2×10⁻⁶ • ∆V
∆V = 6×10⁶ V ✓