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2 C2H11OH + 9 O2 ----> 4 CO2 + 12 H2O
10g C2H11OH × × × = 16.89 g CO2
- Reactivo limite: Oxigeno
2g O2 × × = 0.028 mol CO2
Ahora, para saber cuantos litros se forman, usamos la formula de los gases PV=nRT
despejamos a V.
V=
V= = 0.63 L de CO2
Estudiante de Ing. Química