Question

Uraikanlah unsur-unsur penyusun dari senyawa-senyawa berikut ini beserta jumlahnya!
a.Magnesium nirat (Mg(NO3)2)
b.Besi(III) fostat (FePO4)
c.Natrium sulfida (Na2S)
d.Kalsium nitrida (Ca3N2)
e.Besi (III) klorida (FeCI3)
f.Nitrogen dioksida (NO2)
g.Nitrogen trioksida (NO3)
h.Karbon tetraklorida (CCI4)
i.Asam Nitrat (HNO3)
j.Kalsium karbonat (CaCO3)
saya butuh sekarang!!!

Answer 1

a. Magnesium nitrat (Mg(NO3)2)
   Mg = 1 x 24 = 24
   N   = 1 x 14 = 14
   O   = 6 X 16 = 96
24+14+96 = 134

b. Besi (III) Fosfat (FePO4)
   Fe = 1 x 56 = 56
   P  = 1 x 31 = 31
   O  = 4 x 16 = 64
56+31+64 = 151

c. Natrium sulfida (Na2S)
    Na = 2 x 23 = 46
     S  = 1 x 32 = 32
46+32 = 78

d. Kalsium nitrida (Ca3N2)
   Ca = 3 x 40 = 120
   N   = 2 x 14 = 28
120+28 = 148
 
e. Besi (III) klorida (FeCl3)
   Fe = 1 x 56 = 56
   Cl  = 3 x 35 = 105
56+105 = 161

f. Nitrogen dioksida (NO2)
   N = 1 x 14 = 14
   O = 2 x 16 = 32
14+32 = 46

g. Nitrogen trioksida (NO3)
   N = 1 x 14 = 14
   O = 3 x 16 = 48
14+48 = 62

h. Karbon tetraklorida (CCl4)
   C = 1 x 12 = 12
  Cl = 4 x 35 = 140
12+140 = 152

i. Asam Nitrat (HNO3)
  H = 1 x 1 = 1
  N = 1 x 14 = 14
  O = 3 x 16 = 48
1+14+48 = 63

j. Kalsium karbonat (CaCO3)]
   Ca = 1 x 40 = 40
   C   = 1 x 12 = 12
   O   = 3 x 16 = 48
40+12+48 = 100