Ułóż bilans elektronowy-jonowy dla reakcji:
C2H2 + KMnO4 +H2O ---> HOOH - COOH + MnO2 + KOH
C2H2 + KMnO4 +H2O ---> HOOH - COOH + MnO2 + KOH
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C₂H₂ + KMnO₄ + H₂O --> COOH-COOH + MnO₂ + KOH
Redukcja:
MnO₄⁻ + 2H₂O + 3e ---> MnO₂ + 4OH⁻ /*8
Utlenianie:
C₂H₂ + 8OH⁻ ---> COOH-COOH + 4H₂O + 8e /*3
3C₂H₂ + 8KMnO₄ + 4H₂O --> 3COOH-COOH + 8MnO₂ + 8KOH