Untuk membuat larutan dengan ph 6 kedalam 100 ml larutan asam asetat 0,1 M (ka = 10^-5 ) ditambahkan natrium asetat (Mr = 82 ) sebanyak.....
a 8,2 gram
b 4,2 gram
c 4,1 gram
d 0,82 gram
e 0,41 gram
bantu pakai caranya yaaa
a 8,2 gram
b 4,2 gram
c 4,1 gram
d 0,82 gram
e 0,41 gram
bantu pakai caranya yaaa
fatihahalhusna
![pH=6\\{[H^+]}=10^{-6}\ M\\\\{[H^+]}=Ka\times\frac{mmol\ As.\ asetat}{mmol\ Na.Asetat}\\\\10^{-6}=10^{-5}\times\frac{100\times0,1}{mmol\ Na.Asetat}\\\\mmol\ Na.asetat=100\ mmol\\\\gr\ Na.asetat=\frac{100}{1000}\times82=\boxed{\boxed{\bold{8,2\ gram}}}](https://tex.z-dn.net/?f=pH%3D6%5C%5C%7B%5BH%5E%2B%5D%7D%3D10%5E%7B-6%7D%5C+M%5C%5C%5C%5C%7B%5BH%5E%2B%5D%7D%3DKa%5Ctimes%5Cfrac%7Bmmol%5C+As.%5C+asetat%7D%7Bmmol%5C+Na.Asetat%7D%5C%5C%5C%5C10%5E%7B-6%7D%3D10%5E%7B-5%7D%5Ctimes%5Cfrac%7B100%5Ctimes0%2C1%7D%7Bmmol%5C+Na.Asetat%7D%5C%5C%5C%5Cmmol%5C+Na.asetat%3D100%5C+mmol%5C%5C%5C%5Cgr%5C+Na.asetat%3D%5Cfrac%7B100%7D%7B1000%7D%5Ctimes82%3D%5Cboxed%7B%5Cboxed%7B%5Cbold%7B8%2C2%5C+gram%7D%7D%7D "pH=6\\{[H^+]}=10^{-6}\ M\\\\{[H^+]}=Ka\times\frac{mmol\ As.\ asetat}{mmol\ Na.Asetat}\\\\10^{-6}=10^{-5}\times\frac{100\times0,1}{mmol\ Na.Asetat}\\\\mmol\ Na.asetat=100\ mmol\\\\gr\ Na.asetat=\frac{100}{1000}\times82=\boxed{\boxed{\bold{8,2\ gram}}}")
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amsap
kak bisa jelasin detailnya gk kak kan 100 x 0,1 = 10 trus itu mksudnya mmol na asetat 100 mmol apa yg 10^-6 dibagi 10^-5?
fatihahalhusna
mmol = mL x M ----> mmol As.Asetat=100 mL x 0,1 M = 10 mmol
amsap
iya kak yg itu aku ngerti cuman yg 1oo dibagi 1000 aku gk maksud dapetnya darimana
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