Respuesta:
Explicación:
Datos
m = 35 kg
[tex]\mu_{k}[/tex] = - 0.20 (adimensional)
Fórmula
[tex]\mu_{k}[/tex] = [tex]-\frac{a}{g}[/tex]
- 0.20 = - a/10
2 m/s² = a
∑Fvert = 0
N - W = 0 => N = W = m.g
N = 35*10 = 350 N
2da Ley de Newton
F - [tex]\mu_{k}[/tex].N = m.a
F = ma + [tex]\mu_{k}[/tex].N = 35 * 2 + 0.20 * 350 = 70 + 70
F = 140 N
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Respuesta:
Explicación:
Datos
m = 35 kg
[tex]\mu_{k}[/tex] = - 0.20 (adimensional)
Fórmula
[tex]\mu_{k}[/tex] = [tex]-\frac{a}{g}[/tex]
- 0.20 = - a/10
2 m/s² = a
∑Fvert = 0
N - W = 0 => N = W = m.g
N = 35*10 = 350 N
2da Ley de Newton
F - [tex]\mu_{k}[/tex].N = m.a
F = ma + [tex]\mu_{k}[/tex].N = 35 * 2 + 0.20 * 350 = 70 + 70
F = 140 N