Datos:
P1 = 670 Torr = 89.325,74 Pa
1Torr = 133,322 Pa
670 equivale a X
X = 89.325,74 Pa
T1= 26°C+273=299K
P2 = 940 Torr(133,32Pa /1Torr) = 123.322,68 Pa
V2 = 440ml = 0,00044m³
Si 940 tiene 440 ml
670 tiene X
X = 313,62 ml = 0,03136 m³
Ecuación de los gases ideales:
P1*V1/T1=P2*V2/T2
T2=T1*P2*V2/(P1.V1)
T2= 299K*123322.68*0.00044/89.325,74 Pa*0,03136m³
T2= 5,79K
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Verified answer
Datos:
P1 = 670 Torr = 89.325,74 Pa
1Torr = 133,322 Pa
670 equivale a X
X = 89.325,74 Pa
T1= 26°C+273=299K
P2 = 940 Torr(133,32Pa /1Torr) = 123.322,68 Pa
V2 = 440ml = 0,00044m³
Si 940 tiene 440 ml
670 tiene X
X = 313,62 ml = 0,03136 m³
Ecuación de los gases ideales:
P1*V1/T1=P2*V2/T2
T2=T1*P2*V2/(P1.V1)
T2= 299K*123322.68*0.00044/89.325,74 Pa*0,03136m³
T2= 5,79K