Datos:
V₁ = V₂ = 229 pies³
m₁ = 1 Lb
P₁ = 250 psia
T₁ = ?
T₂ = 100~F = 560 °R
P₂ = ?
PM agua = 18 Lb/mol
R = 10.73159 pie³. psi/Lbmol °R
- El número de moles en 1 Lb de agua (n) es:
n = 1 Lb/18 Lb/Lb-mol → n = 0.556 Lb-mol
- La temperatura inicial (T₁), es;
P₁ x V₁ = n x R x T₁ → T₁ = P₁ x V₁ /n x R
T₁ = 250 psia x 2.29 pie³/(0.556 Lb-mol x 10.73159 pie³ psi/Lbmol °R
→ T₁= 95. 95 °R ( -364 °F)
- La presión final del agua (P₂) a 100 °F, es:
P₂x V₂ = n x R x T₂ → P₂ = n x R x T₂/V₂
→ P₂ = 0.556 Lbmol x 10.73159 psia x pie³/Lbmol°R x 560°R / 2.29 pie³
→ P₂ = 1459.12 psia
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Verified answer
Datos:
V₁ = V₂ = 229 pies³
m₁ = 1 Lb
P₁ = 250 psia
T₁ = ?
T₂ = 100~F = 560 °R
P₂ = ?
PM agua = 18 Lb/mol
R = 10.73159 pie³. psi/Lbmol °R
- El número de moles en 1 Lb de agua (n) es:
n = 1 Lb/18 Lb/Lb-mol → n = 0.556 Lb-mol
- La temperatura inicial (T₁), es;
P₁ x V₁ = n x R x T₁ → T₁ = P₁ x V₁ /n x R
T₁ = 250 psia x 2.29 pie³/(0.556 Lb-mol x 10.73159 pie³ psi/Lbmol °R
→ T₁= 95. 95 °R ( -364 °F)
- La presión final del agua (P₂) a 100 °F, es:
P₂x V₂ = n x R x T₂ → P₂ = n x R x T₂/V₂
→ P₂ = 0.556 Lbmol x 10.73159 psia x pie³/Lbmol°R x 560°R / 2.29 pie³
→ P₂ = 1459.12 psia