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h=3b+2 area=160
a=bh
2
160=bh
2
160(2)=bh
320=bh sustituimos h=3b+2
320=b(3b+2)
320=3b²+2b
3b²+2b-320=0
(3b+32)(b-10)=0
3b+32=0 b-10=0
3b=-32 b=10
b=-32 b=10
3
tomamos el valor positivo
b=10
si b=10
h=3b+2
h=3(10)+2
h=30+2
h=32
la altura mide 32 cm(la base mide 10 cm)