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x+2x-15-48=0
x(al cuadrado)+2x-63=0
a:1 b:2 c:-63
x=\frac{-2+\sqrt{2^2-4\cd\cdot \left(-63\right)}}{2}
x_{1} = \frac{-2+16}{2} = \frac{14}{2}=7
x_{2} = \frac{-2-16}{2} = \frac{-18}{2}=-9
Tomas el valor positivo
x=7