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D = n(n-3)/2 ; n= cantidad de lados del polígono
9 = n (n-3) / 2
18 = n² - 3n
n² - 3n - 18 = 0
(n - 6)(n+3)=0
n= 6
n=-3
Se descarta el valor negativo, por lo tanto se trata de un HEXAGONO (6 lados)