(2n - 1)² = (n+5)² aplicamos raiza cuadrada √
√(2n - 1)² = √(n+5)²
(2n - 1) = (n+5)
2n - n = 5 + 1
n= 6
comprobamos
[(2 x 6)-1]² = (6+5)²
(12-1)² = 11²
11² = 11²
121 = 121
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(2n - 1)² = (n+5)² aplicamos raiza cuadrada √
√(2n - 1)² = √(n+5)²
(2n - 1) = (n+5)
2n - n = 5 + 1
n= 6
comprobamos
[(2 x 6)-1]² = (6+5)²
(12-1)² = 11²
11² = 11²
121 = 121