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T1=25°C +273=298K
P1=600mmhg
V2=?
condiciones normales
T2=0°C=273K
P2=1atm=760mmHg
ley combinada de los gases
VI*P1*T2=V2*P2*T1
DESPEJANDO V2
V2=VI*P1*T2/P2*T1
REEMPLAZANDO VALORES:
V2=(265ml* 600mmHg*273)/(760mmHg*298)=192 ml