Un gas ocupa 5 litros a 300 ºK y 2 atm. Calcule el volumen final a 330 ºK y 4 atm de presión
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Respuesta:
[tex]v2 = \frac{v1p1t2}{p2t1} [/tex]
[tex]v2 = \frac{(5lts)(2atm)(330k)}{4atm(300k)} = \frac{3300lts}{1200 \: lts} = 2.75 \: lts[/tex]