P = 2.210 atm
Aplicar la ley de los gases ideales:
V x P = n x R x T
R = 0.0821 (L atm/mol K)
n = 0.01 moles
V = 0.25 L
T = 400ºC + 273 = 673 K
P = ¿?
Calcular la presión
P = n x R x T
------------------
V
P = 0.01 mol x 0.0821 (L atm/mol K) x 673 K
--------------------------------------------------------------------
0.25 L
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respuesta:
P = 2.210 atm
Explicación:
Aplicar la ley de los gases ideales:
V x P = n x R x T
Datos:
R = 0.0821 (L atm/mol K)
n = 0.01 moles
V = 0.25 L
T = 400ºC + 273 = 673 K
P = ¿?
Calcular la presión
P = n x R x T
------------------
V
P = 0.01 mol x 0.0821 (L atm/mol K) x 673 K
--------------------------------------------------------------------
0.25 L
P = 2.210 atm