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y=Cantidad de trajes de 35
40x+35y=910
x+y=50
de donde x=50-y
40(50-y)+35y=910
2000-40y+35y=910
-5y=910-2000
-5y=-1090
y=-1090/-5
y=218
x=50-218
x=-168
El problema presenta un valor negativo, pero asi se resuelve.