Respuesta:
To solve this problem, the Maximum Common Divisor of the numbers 360 and 150 is calculated:
360 ....................................... 150 ......... ....................... 2
180 ......................................... 75 ....... ........................... 3
60 ........................................... 25 ..... ............................ 5
12 ............................................. 5 ... ................................ *
Looking at the last column, MC D (150, 360) = 2 x 3 x 5 = 30
Then, the length of the side of the square plot with maximum area is
30 meters.
The maximum possible area is 30 meters x 30 meters = 900 square meters.
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Respuesta:
To solve this problem, the Maximum Common Divisor of the numbers 360 and 150 is calculated:
360 ....................................... 150 ......... ....................... 2
180 ......................................... 75 ....... ........................... 3
60 ........................................... 25 ..... ............................ 5
12 ............................................. 5 ... ................................ *
Looking at the last column, MC D (150, 360) = 2 x 3 x 5 = 30
Then, the length of the side of the square plot with maximum area is
30 meters.
The maximum possible area is 30 meters x 30 meters = 900 square meters.