jawab: (a+10) + (b+10) = 72 a + b + 20 = 72 a + b = 72 - 20 a + b = 52 a + 3a = 52 4a = 52 a = 52 : 4 a = 13
b = 3a b = 3.13 b = 39
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Aryabalakosa
Misal umur Udin = a tahun, umur Pak Tohir = 3a tahun. 10 tahun lagi ⇒ (a+10) + (3a+10) = 72 ⇒ 4a = 52 ⇒ a = 13. → usia Udin = a = 13 tahun; usia Pak Tohir = 3a = 3x13 = 39 tahun.
b = 3a
(a+10) + (b+10) = 72
jawab:
(a+10) + (b+10) = 72
a + b + 20 = 72
a + b = 72 - 20
a + b = 52
a + 3a = 52
4a = 52
a = 52 : 4
a = 13
b = 3a
b = 3.13
b = 39