Ubahlah bentuk perpangkatan berikut sehingga menjadi bentuk perkalian berulang,kemudian tentukan nilainya. a) (7)⁻³ b) (4)⁴ c) (-8)⁻⁴ d) (9)⁻² e) (13)⁵
indirakusuma
A. (7)⁻³ = 1/7³ = 1/(7x7x7) = 1/343 b. (4)⁴ = 4x4x4x4 = 256 c. (-8)⁻⁴ = 1/(-8)⁴ = 1/((-8)x(-8)x(-8)x(-8)) = 1/4096 d. (9)⁻² = 1/9² = 1/(9x9) = 1/81 e. 13⁵ = 13x13x13x13x13 = 371.293
b. (4)⁴ = 4x4x4x4 = 256
c. (-8)⁻⁴ = 1/(-8)⁴ = 1/((-8)x(-8)x(-8)x(-8)) = 1/4096
d. (9)⁻² = 1/9² = 1/(9x9) = 1/81
e. 13⁵ = 13x13x13x13x13 = 371.293